如何用Perl将指定格式的数据写入二进制文件?

使用 pack

#! /usr/bin/perl

use warnings;
use strict;

# demo only    
*ARGV = *DATA;

while (<>) {
  my($a,$b) = split;
  $a = join "", reverse $a =~ /(..)/g;
  $b = sprintf "%08x", $b;

  print pack "H*" => $a . $b;
}

__DATA__
2A02FC42 4
70726F67 36
6A656374 471

运行示例:

$ ./prog.pl | od -t x1
0000000 42 fc 02 2a 00 00 00 04 67 6f 72 70 00 00 00 24
0000020 74 63 65 6a 00 00 01 d7
0000030

我的版本(已测试):

my $fout;
if ( ! open( $fout, ">/tmp/deleteme.bin" ) ) {
    die( "Failed to open /tmp/deleteme.bin: $!" );
}
binmode( $fout );

while ( <DATA> ) {
    my ( $left, $right ) = split( /\s+/s, $_ );

    my $output = pack( "VN", hex($left), int($right) );
    printf(
        STDERR
        "  note, %8X %d -> " . ( "%02X" x 8 ) . "\n",
        hex($left), $right,
        map { $_ } unpack( "C8", $output )
    );

    print( $fout $output );
}
close( $fout );

__DATA__
70726F67 36 -> 676F727000000024
6A656374 471 -> 7463656A000001D7

输出:

note, 70726F67 36 -> 676F727000000024
note, 6A656374 471 -> 7463656A000001D7

规范的方法是 pack . 假设您从文本文件中读取的数据已经转换为数字(包括十六进制数字),并存储在vars中 $x $y . 那你应该做些

 print OUTFILE pack("NN", $x, $y);

如果需要不同的字节顺序,则必须使用 NN ,请参见 perldoc -f pack 详情。