删除逗号后的空格和“或此符号前后的空格”

echo preg_replace('/\s+?\'\s+?/', '\'', $text);

简单快速的解决方案只需使用PHP explode 和 implode 功能

echo $text = "'game', ' open world', ' test rpg'";
print_r(implode(',',explode(',', $text)));

试试这个:

<?php
$text = "'game', ' open world', ' test rpg'";
$str = explode(",",$text);
$arr = array();
foreach ($str as $key) {
    array_push($arr, trim($key));
}

print_r(implode(',',$arr));
?>

查看这些PHP函数 implode 和 explode

以下模式应该有效。

Regexr

代码:

$text = "'game', ' open world', ' test rpg'";

echo preg_replace('/(\s?\'\s?)/', "'", $text);

前面的regex答案不解释逗号后的空格(而不是逗号前的空格) ' )例如 open, world . 下面是一个适用于逗号和空格的解决方案:

$text = "'game', ' open, world', ' test ' rpg'";
echo preg_replace("/(?: *(?='))([',]) */", '$1', $text);

选项1:

$text  = explode("', ' ",$text);
$text = implode("','",$text);

选项2:

$text = str_replace("', ' ","','",$text)