一个非常棘手的解决办法是
thread_id
排序依据
view_count
在一个
GROUP_CONCAT
. 然后,我们可以利用字符串操作来获得
最低限度
查看\u计数
在你的
SELECT
子句,而不是
t.thread_id
SUBSTRING_INDEX(GROUP_CONCAT(DISTINCT t.thread_id
ORDER BY t.view_count ASC
SEPARATOR ','),
',',
1) AS thread_id_with_minimum_views
现在,根据
选择
查询以识别具有最小视图的重复记录,
DELETE
查询以从
xf_thread
表格如下:
DELETE t_delete FROM xf_thread AS t_delete
INNER JOIN (SELECT CAST(SUBSTRING_INDEX(GROUP_CONCAT(DISTINCT t.thread_id ORDER BY t.view_count ASC SEPARATOR ','), ',', 1) AS UNSIGNED) AS tid_min_view
FROM (SELECT * FROM xf_thread) t
INNER JOIN xf_post p ON p.thread_id = t.thread_id
WHERE t.first_post_id = p.post_id
AND t.user_id = 0
AND t.reply_count < 2
GROUP BY t.title, t.username, p.message
HAVING Count(t.title) > 1
AND Count(t.username) > 1
AND Count(p.message) > 1
ORDER BY t.thread_id) AS t_dup
ON t_delete.thread_id = t_dup.tid_min_view