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如何获取S3中具有Key Error和异常的对象列表

boto3 amazon-s3 amazon-web-services

0

Scarface Jr · 技术社区 · 2 年前

I am new to this AWS boto3 concepts .The below code is giving a Key error  and some exception  that i am trying to execute can someone look to it and try to solve if any errors?

import boto3

def list_s3_objects(bucket_name):
    s3 = boto3.client('s3')
    objects = []
    try:
        response = s3.list_objects_v2(Bucket=bucket_name)
        for obj in response['Contents']:
            objects.append(obj['Key'])
    except Exception as e:
        print(f"An error occurred in the following ie,: {e}")
    return objects

def main():
    bucket_name = 'name of my bucket'
    objects = list_s3_objects(bucket_name)
    print("S3 Objects to be created are:")
    for obj in objects:
        print(obj)

if __name__ == "__main__":
    main()

我尝试了不同的异常处理,甚至我的登录详细信息都是正确的。但它也显示出关键错误。我只是想打印我的s3 bucket对象。

1 回复 | 直到 2 年前

1

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Anudeep K S 2 年前

The below code lists the s3 objects as you have specified. Here I have added the paginator and botocore.exceptions for checking exception.  Thank you

import boto3
from botocore.exceptions import ClientError

def list_s3_objects(bucket_name):
    s3 = boto3.client('s3')
    objects = []
    try:
        paginator = s3.get_paginator('list_objects_v2')
        for page in paginator.paginate(Bucket=bucket_name):
            if 'Contents' in page:
                for obj in page['Contents']:
                    objects.append(obj['Key'])
    except ClientError as e:
        print(f"Error occurred is: {e}")
    return objects

def main():
    bucket_name = 'my-bucket'
    objects = list_s3_objects(bucket_name)
    print("S3 Objects are :")
    for obj in objects:
        print(obj)

if __name__ == "__main__":
    main()