A.
dplyr
基于解决方案使用
lag
和
mutate
可通过以下方式实现:
library(dplyr)
data %>% mutate(x = as.numeric(x), y = as.numeric(y)) %>%
mutate(prof_x = ifelse(act_x == "Buy", lag(x)-x, x-lag(x))) %>%
mutate(prof_y = ifelse(act_y == "Buy", lag(y)-y, y-lag(y)))
#
# x y act_x act_y prof_x prof_y
# 1 0 11 Short Buy NA NA
# 2 2 5 Buy Short -2 -6
# 3 8 14 Short Buy 6 -9
# 4 1 9 Buy Short 7 -5
# 5 7 13 Short Buy 6 -4
# 6 10 7 Buy Short -3 -6
# 7 15 4 Short Buy 5 3
# 8 14 0 Buy Short 1 -4
# 9 13 12 Short Buy -1 -12
# 10 11 8 Buy Short 2 -4
数据:
data <- data.frame(x = c("0", "2", "8", "1", "7", "10", "15", "14", "13", "11"),
y = c("11", "5", "14", "9", "13", "7", "4", "0", "12", "8"),
act_x = c("Short", "Buy", "Short", "Buy", "Short", "Buy", "Short", "Buy", "Short", "Buy"),
act_y = c("Buy", "Short", "Buy", "Short", "Buy", "Short", "Buy", "Short", "Buy", "Short"),
stringsAsFactors = FALSE)