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如何将对象从活动传递到片段?

parcelable android-fragments json android

0

Zolly · 技术社区 · 7 年前

我想把对象(我通过改装得到的)传递给片段。我听说过两种方法,但这两种方法都有问题。我想通过 FullForecast 反对我的碎片。

使用 Parcelize . 我在类上实现了它,但它与我的构造函数冲突。

我听说我可以将JSON字符串从活动传递到片段,然后在片段内将其转换为对象。但是,我无法从JSON调用中获取JSON字符串。我试过了 Call<ResponseBody> 是的。 response.body().toString() ,但没有得到JSON字符串

这是我的密码

repository.getWeatherForecast(place,
                object : Callback<FullForecast> {
                    override fun onFailure(call: Call<FullForecast>?, t: Throwable?) {
                        println("onFailure")
                    }

                    override fun onResponse(call: Call<FullForecast>?, response: Response<FullForecast>?) {
                        if (response != null && response.isSuccessful && response.body() != null) {

                            forecastObj = response.body() as FullForecast
                            // Try to get Json string here
                        }
                    }
                })

@JsonClass(generateAdapter = true)
data class FullForecast(@Json(name = "list")
                        val forecastList: List<WeatherForecast>) {
}

@JsonClass(generateAdapter = true)
data class WeatherForecast(@Json(name = "main")
                           val weatherDetail: WeatherDetail,

                           @Json(name = "weather")
                           val weatherIcon: List<WeatherIcon>,

                           @Json(name = "dt_txt")
                           val date: String) {
}

@JsonClass(generateAdapter = true)
data class Place(@Json(name = "main")
                 val weatherDetail: WeatherDetail,

                 @Json(name = "weather")
                 val weatherIcon: List<WeatherIcon>,

                 @Json(name = "sys")
                 val countryDetail: CountryDetail,

                 @Json(name = "dt_txt")
                 var forecastDate: String = "",

                 val name: String,

                 var placeIdentifier: String = "",

                 var lastUpdated: String = "") {
}

@JsonClass(generateAdapter = true)
data class CountryDetail(val country: String) {
}

@JsonClass(generateAdapter = true)
data class WeatherDetail(@Json(name = "temp")
                         val temperature: Double,
                         val temp_min: Double,
                         val temp_max: Double) {
}

@JsonClass(generateAdapter = true)
data class WeatherIcon(val icon: String) {
}

3 回复 | 直到 7 年前

1

0

GianhTran 7 年前

你应该实施 Parcelize 如下所示

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class FullForecast(@Json(name = "list")
  val forecastList: List<WeatherForecast>) : Parcelable {
  }

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class WeatherForecast(@Json(name = "main")
  val weatherDetail: WeatherDetail,

      @Json(name = "weather")
      val weatherIcon: List<WeatherIcon>,

      @Json(name = "dt_txt")
      val date: String) : Parcelable {
  }

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class Place(@Json(name = "main")
  val weatherDetail: WeatherDetail,

      @Json(name = "weather")
      val weatherIcon: List<WeatherIcon>,

      @Json(name = "sys")
      val countryDetail: CountryDetail,

      @Json(name = "dt_txt")
      var forecastDate: String = "",

      val name: String,

      var placeIdentifier: String = "",

      var lastUpdated: String = "") : Parcelable {
  }

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class CountryDetail(val country: String) : Parcelable {
  }

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class WeatherDetail(@Json(name = "temp")
  val temperature: Double,
      val temp_min: Double,
      val temp_max: Double) : Parcelable {
  }

  @Parcelize
  @JsonClass(generateAdapter = true)
  data class WeatherIcon(val icon: String) : Parcelable {
  }

如果您遇到错误:

这是IDE本身的一个已知bug,您可以忽略它,代码没有任何错误,并且可以按预期工作。你可以跟踪这个问题 here .

2

0

code4rox 7 年前

尝试 EventBus 将对象传递到片段。

3

0

Vishnu Magar 7 年前

跟着这个走

步骤1: 使对象实现可序列化

前任。 public class Match implements Serializable { }

第2步:将对象打包并传递给活动或片段

前任。

Bundle args = new Bundle();
args.putSerializable("ARG_PARAM1", yourObject);

步骤3:像这样获取对象表单包

 yourObj = (Match) getArguments().getSerializable(ARG_PARAM1);