将方法调用及其参数传递给其他方法

我正在使用一个外部自动化库,其中包含一组参数为1或2的API,这些参数随机抛出TargetInvocationException。第二次或第三次调用这些API通常有效。因此,我创建了两个助手方法来封装多重重试逻辑

//Original API calls
bool result1 = Foo1(true);
int result2 = Foo2(4, "abc");

//New API calls
bool result1 = SafeMethodCall(Foo1, true);
int result2 = SafeMethodCall(Foo2, 4, "abc");


//Helper Methods
public static TResult SafeMethodCall<T, TResult>(
    Func<T, TResult> unSafeMethod,
    T parameter)
{
    int numberOfMethodInvocationAttempts = 3;
    int sleepIntervalBetweenMethodInvocations = 10000;

    for (int i = 0; i < numberOfMethodInvocationAttempts; i++)
    {
        try
        {
            return unSafeMethod(parameter);
        }
        catch (System.Reflection.TargetInvocationException ex)
        {
            System.Threading.Thread.Sleep(sleepIntervalBetweenMethodInvocations);
        }
    }
}

public static TResult SafeTargetInvocationMethodCall<T1, T2, TResult>(
    Func<T1, T2, TResult> unSafeMethod,
    T1 parameter1,
    T2 parameter2)
{
    int numberOfMethodInvocationAttempts = 3;
    int sleepIntervalBetweenMethodInvocations = 10000;

    for (int i = 0; i < numberOfMethodInvocationAttempts; i++)
    {
        try
        {
            return unSafeMethod(parameter1, parameter2);
        }
        catch (System.Reflection.TargetInvocationException ex)
        {
            System.Threading.Thread.Sleep(sleepIntervalBetweenMethodInvocations);
        }
    }
}

问题:如果您看到上面的两个助手方法具有相同的主体,唯一的区别是Try块内的unsafemethod调用。在这里我如何避免代码重复,因为我可能需要添加一个接受

Func<TResult>

作为另一个参数类型。