可以使用Boost.Regex解析流吗?

#include <iostream>
#include <string>
#include <boost/foreach.hpp>
#include <boost/regex.hpp>
#include <boost/range.hpp>

using namespace std;
using namespace boost;

int main()
{
    regex re
    (
        "("
            "([a-z]+)|"
            "(-?[0-9]+(\\.[0-9]+)?)"
        ")"
    );

    string s = "here is a\t list of Words. and some 1239.32 numbers to 3323 parse.";
    sregex_iterator m1(s.begin(), s.end(), re), m2;

    BOOST_FOREACH (const match_results<string::const_iterator>& what, make_iterator_range(m1, m2)) {
        cout << ":" << what[1].str() << ":" << what.position(1) << ":" << what.length(1) << endl;
    }

    return 0;
}

有没有办法告诉正则表达式从流而不是字符串进行解析?似乎应该可以使用任何迭代器。