Thread.sleep在前一代码之前激活

此代码将检查一行中的三个按钮是否具有相同的文本。如果是,它会将这些按钮的颜色更改为绿色,并将int计数器更改为9。当它超过这段代码时,它将重置所有按钮的原始状态,因为计数器==9。

问题是,它会在按钮变绿之前休眠。为什么?

int counter = 0;

private void winCheck(String sign)
{
    if (jButton1.getText().equals(sign))
    {
        if (jButton2.getText().equals(sign))
        {
            if (jButton3.getText().equals(sign))
            {
                jButton1.setBackground(Color.GREEN);
                jButton2.setBackground(Color.GREEN);
                jButton3.setBackground(Color.GREEN);
                counter = 9;   
            }

            try {
                    Thread.sleep(1000);
                } 
            catch(InterruptedException ex) 
                {
                    Thread.currentThread().interrupt();
                }
        }
}

// This last part to show what I mean with reset.
counter++;

    if (counter == 10)
    {
        jButton1.setBackground(null);
        jButton1.setText(" ");

        counter = 0;
    }