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如何制作此系统。可序列化类不可知?

unity3d c#

Olivier Pons · 技术社区 · 7 年前

原则如下:

我有很多Ajax交换
我有一个 System.Serializable 类是Ajax调用的结果
我总是有两个功能:
- 调用的函数
- 分析调用的函数

进行调用的函数获取一个回调作为参数,进行调用,完成后,使用 系统可序列化 班

下面是一个示例:

[System.Serializable]
public class JsonState
{
    public int state;
    public string message;
    public JsonData data;
}

在我的课堂上:

public class DataController : MonoBehaviour {
    public delegate void CallbackAjaxStateFinished(JsonState j);
    public CallbackAjaxStateFinished cbAjaxStateFinished = null;

    public void AjaxStateGet(CallbackAjaxStateFinished cb=null)
    {
        /* make the Ajax call*/
        cbAjaxStateFinished = cb;
        new HTTPRequest(
            new Uri(baseURL + _urlGetState),
            HTTPMethods.Get, AjaxStateGetFinished
        ).Send();
    }

    private void AjaxStateGetFinished(
        HTTPRequest request, HTTPResponse response
    ) {
        if (response == null) {
            return;
        }
        JsonState j = null;
        try {
            j = JsonUtility.FromJson<JsonState>(response.DataAsText);
            if (cbAjaxStateFinished != null) {
                cbAjaxStateFinished(j);
            }
        } catch (ArgumentException) { /* Conversion problem */
            TryDisplayFatalError(FatalErrors[FatalError.ConversionProblem2]);
        }
    }
}

问题是,我已经有了3个这样的Ajax调用,始终遵循相同的原则,下面是3个回调,让您概括一下:

public CallbackAjaxStateFinished cbAjaxStateFinished = null;
public CallbackAjaxGamesToJoinFinished cbAjaxGamesToJoinFinished = null;
public CallbackAjaxGameDetailFinished cbAjaxGameDetailFinished = null;

但我将添加另一个,并复制/粘贴代码以发送/接收上述内容,只需进行2个小修改:

更改 CallbackXxx 类型
更改 系统可序列化 班

我是C#新手,有没有办法让这个通用?

1 回复 | 直到 7 年前

Olivier Pons 7 年前

这个过程并没有那么复杂,假设您的回调总是这样 void(SomeStateclass) .

更换 JSonState 在上面的代码中使用泛型T可以实现这一目的。这就是你最终的结果:

// The DataController takes a generic T respresenting one of your State classes
// notice that we need a constraint for the type T to have a parameterless constructor
public class DataController<T> : MonoBehaviour where T: new()
{ 
    // the delegate takes the generic type, so we only need one
    public delegate void CallbackAjaxFinished(T j);

    public CallbackAjaxFinished cbAjaxFinished = null;

    public void AjaxStateGet(CallbackAjaxFinished cb=null)
    {
        /* make the Ajax call*/
        cbAjaxFinished = cb;
        new HTTPRequest(
            new Uri(baseURL + _urlGetState),
            HTTPMethods.Get, AjaxStateGetFinished
        ).Send();
    }

    private void AjaxStateGetFinished(
        HTTPRequest request, HTTPResponse response
    ) {
        if (response == null) {
            return;
        }
        // here we use the default keyword to get 
        // an instance of an initialized stronglytyped T
        T j = default(T);
        try {
            // the T goes into the FromJson call as that one was already generic
            j = JsonUtility.FromJson<T>(response.DataAsText);
            if (cbAjaxFinished != null) {
                cbAjaxFinished(j);
            }
        } catch (ArgumentException) { /* Conversion problem */
            TryDisplayFatalError(FatalErrors[FatalError.ConversionProblem2]);
        }
    }
}

仅此而已。您的datacontroller类现在是泛型的。

您可以这样使用它:

var dc = new DataController<JsonState>()
dc.AjaxStateGet( (v) => {
   v.Dump("jsonstate");
});

var dc2 = new DataController<JsonState2>();
dc2.AjaxStateGet( (v) => {
   v.Dump("jsonstate2");
});