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指定的填充模式对此算法-c#-系统无效。安全密码学

  •  9
  • bradley  · 技术社区  · 8 年前

    指定的密钥不是此算法的有效大小

    这是我的加密和解密

    “cipherKey”:“0123456789abcdef”,“cipherVector”: “somereallycooliv”

    using System;
    using System.Security.Cryptography;
    using System.IO;
    using System.Text;
    
    namespace DataApi
    {
    public class Encryption
    {
        private readonly IConfigurationService _configService;
    
    
        private const string _vector = "cipherVector";
        private const string _key = "cipherKey";
    
        public Encryption(IConfigurationService configService)
        {
            _configService = configService;
        }
        public string EncryptString(string text)
        {
            if(string.IsNullOrEmpty(text))
            {
                return "";
            }
            try
            {
    
          var key = Encoding.UTF8.GetBytes(_configService.Get(_key));
            byte[] IV = Encoding.ASCII.GetBytes(_configService.Get(_vector));
    
            using (var aesAlg = Aes.Create())
            {
                using (var encryptor = aesAlg.CreateEncryptor(key, IV))
                {
                    using (var msEncrypt = new MemoryStream())
                    {
                        using (var csEncrypt = new CryptoStream(msEncrypt, encryptor, CryptoStreamMode.Write))
                        using (var swEncrypt = new StreamWriter(csEncrypt))
                        {
                            swEncrypt.Write(text);
                        }
    
                        var decryptedContent = msEncrypt.ToArray();
    
                        var result = new byte[IV.Length + decryptedContent.Length];
    
                        Buffer.BlockCopy(IV, 0, result, 0, IV.Length);
                        Buffer.BlockCopy(decryptedContent, 0, result, IV.Length, decryptedContent.Length);
    
                        return Convert.ToBase64String(result);
                    }
                }
            }
            }
            catch(Exception e) {
                 Loggifer.Error("Unable to encrypt string: "+text , e );
    
                throw e;
            }
        }
    
        public string DecryptString(string cipherText)
        {
            if(string.IsNullOrEmpty(cipherText))
            {
                return "";
            }
            try
            {
                var fullCipher = Convert.FromBase64String(cipherText);
    
                byte[] IV = Encoding.ASCII.GetBytes(_configService.Get(_vector));
                var cipher = new byte[16];
    
                Buffer.BlockCopy(fullCipher, 0, IV, 0, IV.Length);
                Buffer.BlockCopy(fullCipher, IV.Length, cipher, 0, IV.Length);
                var key = Encoding.UTF8.GetBytes(_configService.Get(_key));
    
                using (var aesAlg = Aes.Create())
                {
                    using (var decryptor = aesAlg.CreateDecryptor(key, IV))
                    {
                        string result;
                        using (var msDecrypt = new MemoryStream(cipher))
                        {
                            using (var csDecrypt = new CryptoStream(msDecrypt, decryptor, CryptoStreamMode.Read))
                            {
                                using (var srDecrypt = new StreamReader(csDecrypt))
                                {
                                    result = srDecrypt.ReadToEnd();
                                }
                            }
                        }
    
                        return result;
                    }
                }
            }
            catch (Exception e)
            {
                Loggifer.Error("Unable to decrypt string: "+cipherText , e );
                throw e;
            }
        }
    
    }
    }
    
    1 回复  |  直到 8 年前
        1
  •  23
  •   Soumen Mukherjee David F    8 年前

    需要对功能进行两次更改 public string DecryptString(string cipherText)

     var cipher = new byte[fullCipher.Length - IV.Length];
    

     Buffer.BlockCopy(fullCipher, IV.Length, cipher, 0, fullCipher.Length - IV.Length);