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XmlSerializer不反序列化列表<string>

xmlserializer xml .net c#

0

V0ldek · 技术社区 · 7 年前

我试图序列化和反序列化的类(大致上):

class MyDto
{
    public string Name { get; set; }

    private List<string> _uniqueNameStrings = new List<string>();

    [XmlArray("UniqueNames")]
    [XmlArrayItem("string")]
    public List<string> UniqueNameStrings 
    { 
       get => _uniqueNameStrings; 
       set => _uniqueNameStrings = value ?? new List<string>(); 
    }
}

null -正在检查,也不工作:

class MyDto
{
    public string Name { get; set; }

    [XmlArray("UniqueNames")]
    [XmlArrayItem("string")]
    public List<string> UniqueNameStrings { get; set; }
}

为此类生成的架构:

<xs:complexType name="MyDto">
    <xs:sequence>
        <xs:element minOccurs="0" maxOccurs="1" name="Name" nillable="true" type="xs:string" />
        <xs:element minOccurs="0" maxOccurs="1" name="UniqueNames" type="ArrayOfString" />
    </xs:sequence>
</xs:complexType>
<xs:complexType name="ArrayOfString">
    <xs:sequence>
        <xs:element minOccurs="0" maxOccurs="unbounded" name="string" nillable="true" type="xs:string" />
    </xs:sequence>
</xs:complexType>

以及序列化的效果:

<MyDto>
    <Name>MyDtoName</Name>
    <UniqueNames>
        <string>SomeName</string>
        <string>SomeOtherName</string>
        <!-- ... <-->
    </UniqueNames>
</MyDto>

using System.IO.Abstractions;

private IFileSystem _fileSystem;

public void SerializeDto(object dto, string filePath)
{
    var serializer = new XmlSerializer(dto.GetType());

    using (var streamWriter = _fileSystem.FileStream.Create(filePath, FileMode.Create, FileAccess.Write))
    {
        serializer.Serialize(streamWriter, dto);
        streamWriter.Flush();
    }
}

public T DeserializeDto<T>(string filePath) where T : class
{
    var serializer = new XmlSerializer(typeof(T));

    using (var streamReader = _fileSystem.FileStream.Create(filePath, FileMode.Open, FileAccess.Read))
    {
        return (T) serializer.Deserialize(streamReader);
    }
}

这个 Name 属性(以及为简单起见省略的所有其他属性)被正确反序列化,而 UniqueNames set 方法,我可以看到反序列化程序使用 value 相当于空的 List<string> ,好像 <string>

2 回复 | 直到 7 年前

1

0

Parrish Husband 7 年前

试试这个:

[XmlRoot]
public class MyDto
{
    [XMLElement]
    public string Name { get; set; }

    [XmlArray("UniqueNames"), XmlArrayItem("UniqueName")]
    public List<string> UniqueNameStrings { get; set; }

    public MyDto() { }
}

试一试这个序列化程序:

public static void Serialize<T>(T t, string filePath, bool overwrite = true)
{
    using (var fs = new FileStream(filePath, overwrite ? FileMode.Create : FileMode.CreateNew, FileAccess.Write))
    {
        var serializer = new XmlSerializer(typeof(T));
        var ns = new XmlSerializerNamespaces();
        ns.Add("", ""); // Omits xmlns:xsi/xmlns:xsd

        try
        {
            serializer.Serialize(fs, t, ns);
        }
        catch (System.Exception)
        {
            if (File.Exists(filePath))
                File.Delete(filePath);

            throw;
        }
    }
}

2

0

Bouke 7 年前

例子:

XML格式:

<Names>
    <Names>John</Names>
    <Names>Doe</Names>
    <Names>Martin</Names>
    <Names>Looter</Names>
</Names>

C#:

public class Configuration
{
    [XmlArray("Names")]
    [XmlArrayItem("Names")]
    public List<string> Names { get; set; }

    public Load(Stream stream) 
    {
        var xmlSerializer = new XmlSerializer(typeof(Configuration));
        var config = (Configuration)xmlSerializer.Deserialize(stream);
        return config;
    }

}

使用配置名称