代码之家 › 专栏 › 技术社区 › Rod

MySQL order by rand()按天分组

sql-order-by random mysql

3

Rod · 技术社区 · 16 年前

有可能在同一天内得到随机物品吗?

例如:

+----+---------------------+  
| id | md                  |  
+----+---------------------+  
|  1 | 2010-06-27 11:26:01 |  
|  2 | 2010-06-27 11:28:20 |  
|  3 | 2010-06-27 11:29:46 |  
|  4 | 2010-06-27 11:30:50 |  
|  5 | 2010-06-27 12:20:56 |  
|  6 | 2010-06-27 12:27:42 |  
|  7 | 2010-06-27 15:14:05 |  
|  8 | 2010-07-06 01:53:33 |  
|  9 | 2010-07-06 01:52:52 |  
+----+---------------------+

我想在同一天内随机挑选物品,但同时我想按日期说明订购。类似于:

+----+---------------------+  
| id | md                  |  
+----+---------------------+  

|  8 | 2010-07-06 01:53:33 |  random block  
|  9 | 2010-07-06 01:52:52 |  

|  2 | 2010-06-27 11:28:20 |  random block  
|  4 | 2010-06-27 11:30:50 |  
|  1 | 2010-06-27 11:26:01 |  
|  6 | 2010-06-27 12:27:42 |  
|  3 | 2010-06-27 11:29:46 |  
|  5 | 2010-06-27 12:20:56 |  
|  7 | 2010-06-27 15:14:05 |  

+----+---------------------+

因为order by rand()不接受分组,所以不知道如何开始,也不知道这是否可行。

4 回复 | 直到 16 年前

1

4

kennytm 16 年前

可能效率不高,但试试看

select * from (select * from tbl order by rand()) as t group by date(md)

2

5

pouya 14 年前

非常简单:

SELECT * 
FROM tbl 
ORDER BY md DESC, RAND()

3

2

Mike 16 年前

如果我正确地理解了你的问题,这应该可以做到:

SELECT * FROM table1 ORDER BY DATE(md) DESC, RAND();

DROP TABLE IF EXISTS `table1`;

CREATE TABLE `table1` (
    `id` int(11) NOT NULL auto_increment,
    `md` DATETIME,
    PRIMARY KEY  (`id`)
) ENGINE=InnoDB;

DELIMITER //
DROP PROCEDURE IF EXISTS autofill//
CREATE PROCEDURE autofill()
BEGIN
    DECLARE i INT DEFAULT 0;
    WHILE i < 50 DO
        INSERT INTO table1 (md) VALUES (DATE_ADD(NOW(), INTERVAL FLOOR(RAND() * 1000) HOUR));
        SET i = i + 1;
    END WHILE;
END;
//
DELIMITER ;

CALL autofill();

SELECT * FROM table1 ORDER BY DATE(md) DESC, RAND();

+----+---------------------+
| id | md                  |
+----+---------------------+
|  8 | 2010-08-16 13:46:04 |
| 16 | 2010-08-15 19:46:05 |
| 47 | 2010-08-15 18:46:06 |
| 25 | 2010-08-15 15:46:05 |
| 33 | 2010-08-15 09:46:05 |
|  3 | 2010-08-14 20:46:04 |
| 45 | 2010-08-13 03:46:06 |
| 17 | 2010-08-12 13:46:05 |
| 12 | 2010-08-12 06:46:05 |
|  7 | 2010-08-12 15:46:04 |
| 37 | 2010-08-12 14:46:05 |
| 40 | 2010-08-10 05:46:06 |
| 13 | 2010-08-09 10:46:05 |
|  4 | 2010-08-09 00:46:04 |
|  1 | 2010-08-06 12:46:04 |
| 28 | 2010-08-02 23:46:05 |
| 15 | 2010-08-02 10:46:05 |
|  2 | 2010-08-02 01:46:04 |
| 38 | 2010-07-31 13:46:06 |
| 27 | 2010-07-31 04:46:05 |
| 30 | 2010-07-31 03:46:05 |
| 22 | 2010-07-31 08:46:05 |
| 50 | 2010-07-30 05:46:06 |
| 11 | 2010-07-28 13:46:05 |
| 18 | 2010-07-28 21:46:05 |
| 29 | 2010-07-27 23:46:05 |
| 35 | 2010-07-27 11:46:05 |
|  6 | 2010-07-26 20:46:04 |
| 20 | 2010-07-25 03:46:05 |
| 31 | 2010-07-23 07:46:05 |
| 14 | 2010-07-23 23:46:05 |
| 23 | 2010-07-23 10:46:05 |
| 48 | 2010-07-23 17:46:06 |
| 42 | 2010-07-21 03:46:06 |
| 39 | 2010-07-20 05:46:06 |
| 36 | 2010-07-18 05:46:05 |
| 10 | 2010-07-17 01:46:05 |
| 32 | 2010-07-16 06:46:05 |
|  9 | 2010-07-16 15:46:04 |
| 24 | 2010-07-16 10:46:05 |
| 43 | 2010-07-16 09:46:06 |
|  5 | 2010-07-14 01:46:04 |
| 21 | 2010-07-14 08:46:05 |
| 49 | 2010-07-13 07:46:06 |
| 41 | 2010-07-13 15:46:06 |
| 46 | 2010-07-12 04:46:06 |
| 44 | 2010-07-11 16:46:06 |
| 26 | 2010-07-10 14:46:05 |
| 34 | 2010-07-09 16:46:05 |
| 19 | 2010-07-07 01:46:05 |
+----+---------------------+

4

1

animuson 16 年前

你可以用WHERE子句。。。

WHERE date = 'insert date' ORDER BY rand() LIMIT 1`

然后只需使用PHP在每个日期的字符串中插入任何日期。

或者只使用一个MySQL查询,只需按日期降序排列,然后使用PHP将它们全部提取出来。。。

while ($item = mysql_fetch_array($query)):
    // process to figure out the date (I'm sure you can do that)
    $mydates[$date][] = $id; // add that ID to that date array
endwhile;
foreach ($mydates as $date):
    $key = array_rand($date);
endforeach;