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XmlSerializer在PowerShell中的功能?

xmlserializer powershell

7

Ariel · 技术社区 · 16 年前

有没有一种方法可以利用PowerShell中.NET的XmlSerializer类的功能?

更具体地说,能够轻松地将.NET类型反序列化为Xml,例如。

XmlSerializer s = new XmlSerializer(typeof(MyType));
TextReader r = new StreamReader("sample.xml");
MyType myType = (MyType)s.Deserialize(r);
r.Close();

我知道我可以从PowerShell调用上面的代码,但是有没有办法避免在单独的程序集中定义MyType?谢谢

1 回复 | 直到 16 年前

1

10

Community Mohan Dere 9 年前

当然,您可以在Powershell中定义一个类型,并在序列化中使用它。

第一步是定义一个新类型。在 Powershell 2.0 ,你可以通过打电话 Add-Type

第2步是像平常一样使用XmlSerializer类——只需将问题中提供的C代码翻译成Powershell。

下面的示例演示了。它定义一个简单类型,然后从XML字符串反序列化以创建该类型的新实例。然后打印出反序列化实例上的属性值。

$source1 = @"
using System;
using System.Xml;
using System.Xml.Serialization;

namespace MyDynamicTypes
{
    [XmlRoot]
    public class Foo
    {
    [XmlElement]
    public string Message { get; set; }

    [XmlAttribute]
    public int Flavor { get; set; }
    }
}
"@

Add-Type -TypeDefinition $source1 -Language "CSharpVersion3" -ReferencedAssemblies System.Xml.dll

$xml1 = @"
<Foo Flavor='19'>
  <Message>Ephesians 5:11</Message>
</Foo>
"@

$f1 = New-Object MyDynamicTypes.Foo
$sr = New-Object System.IO.StringReader($xml1)
$s1 = New-Object System.Xml.Serialization.XmlSerializer( $f1.GetType() )
$xtr = New-Object System.Xml.XmlTextReader($sr)
$foo = $s1.Deserialize($xtr)

Write-Output ("foo.Flavor = " + $foo.Flavor)
Write-Output ("foo.Message = " + $foo.Message)

感谢 Keith Hill 对于指向,请键入out。

在Powershell 1.0中,您可以使用一些自定义代码执行类似的操作(请参见 Powershell: compiling c# code stored in a string ) .

function Compile-Code {
param (
    [string[]] $code       = $(throw "The parameter -code is required.")
  , [string[]] $references = @()
  , [switch]   $asString   = $false
  , [switch]   $showOutput = $false
  , [switch]   $csharp     = $true
  , [switch]   $vb         = $false
)

$options    = New-Object "System.Collections.Generic.Dictionary``2[System.String,System.String]";
$options.Add( "CompilerVersion", "v3.5")

if ( $vb ) {
    $provider = New-Object Microsoft.VisualBasic.VBCodeProvider $options
} else {
    $provider = New-Object Microsoft.CSharp.CSharpCodeProvider $options
}

$parameters = New-Object System.CodeDom.Compiler.CompilerParameters

@( "mscorlib.dll", "System.dll", "System.Core.dll", "System.Xml.dll", ([System.Reflection.Assembly]::GetAssembly( [PSObject] ).Location) ) + $references | Sort -unique |% { $parameters.ReferencedAssemblies.Add( $_ ) } | Out-Null

$parameters.GenerateExecutable = $false
$parameters.GenerateInMemory   = !$asString
$parameters.CompilerOptions    = "/optimize"

if ( $asString ) {
    $parameters.OutputAssembly = [System.IO.Path]::GetTempFileName()
}

$results = $provider.CompileAssemblyFromSource( $parameters, $code )

if ( $results.Errors.Count -gt 0 ) {
    if ( $output ) {
    $results.Output |% { Write-Output $_ }
    } else {
    $results.Errors |% { Write-Error $_.ToString() }
    }
} else {
    if ( $asString ) {
    $content = [System.IO.File]::ReadAllBytes( $parameters.OutputAssembly )
    $content = [Convert]::ToBase64String( $content )

    [System.IO.File]::Delete( $parameters.OutputAssembly );

    return $content
    } else {
    return $results.CompiledAssembly
    }
}
}

$source1 = @"
using System;
using System.Xml;
using System.Xml.Serialization;

namespace MyDynamicTypes
{
    [XmlRoot]
    public class Foo
    {
    [XmlElement]
    public string Message { get; set; }

    [XmlAttribute]
    public int Flavor { get; set; }
    }
}
"@

Compile-Code -csharp -code $source1

$xml1 = @"
<Foo Flavor='19'>
  <Message>Ephesians 5:11</Message>
</Foo>
"@

$f1 = New-Object MyDynamicTypes.Foo
$sr = New-Object System.IO.StringReader($xml1)
$s1 = New-Object System.Xml.Serialization.XmlSerializer( $f1.GetType() )
$xtr = New-Object System.Xml.XmlTextReader($sr)
$foo = $s1.Deserialize($xtr)

Write-Output ("foo.Flavor = " + $foo.Flavor)
Write-Output ("foo.Message = " + $foo.Message)