使用MVVM的数据模板驱动的视图注入

我有一个像这样的容器视图

<UserControl x:Class="Views.ContainerView">
    <UserControl.Resources>
        <ResourceDictionary>
            <DataTemplate DataType="{x:Type viewmodels:AViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:BViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:CViewModel}">
                <views:MyView />
            </DataTemplate>
            <DataTemplate DataType="{x:Type viewmodels:DViewModel}">
                <views:MyView />
            </DataTemplate>
        </ResourceDictionary>
    </UserControl.Resources>
    <Grid>
        <ListBox ItemsSource="{Binding Path=AvailableViewModels}" 
            SelectedItem="{Binding Path=CurrentViewModel}" 
            IsSynchronizedWithCurrentItem="True" />
        <ContentControl Content="{Binding Path=CurrentViewModel}" />
    </Grid>
</UserControl>

我的所有视图模型都继承了BaseViewModel,所以我将视图转换为

<UserControl x:Class="Views.ContainerView">
    <UserControl.Resources>
        <ResourceDictionary>
            <DataTemplate DataType="{x:Type viewmodels:BaseViewModel}">
                <views:MyView />
            </DataTemplate>
        </ResourceDictionary>
    </UserControl.Resources>
    <StackPanel>
        <ListBox ItemsSource="{Binding Path=AvailableViewModels}" 
            SelectedItem="{Binding Path=CurrentViewModel}" 
            IsSynchronizedWithCurrentItem="True" />
        <ContentControl Content="{Binding Path=CurrentViewModel}" />
    </StackPanel>
</UserControl>

认为它只会实例化一个MyView,并在ListBox.SelectedItem更改时重新绑定ViewModel。我是否正确理解这种行为?这是首选做法吗?当我在视图之间切换时,如何验证我没有搅乱内存?