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将值插入字典数组

dictionary swift ios

user8411642 · 技术社区 · 8 年前

我有一个字典数组,其中有两个字典,如下所示。。

[
{
    "sellingPrice" : "499",
    "id" : "5",
    "quantity" : "-2",
    "transaction_id" : "",
    "shipping_charges" : "",
    "payment_method" : "",
    "taxes" : "",
    "applied_coupon_code" : "",
    "discount_price" : "",
    "transaction_type" : "",
    "remaining_balance" : "",
    "grand_total" : ""
   },
   {
    "sellingPrice" : "500",
    "id" : "8",
    "quantity" : "79",
    "transaction_id" : "",
    "shipping_charges" : "",
    "payment_method" : "",
    "taxes" : "",
    "applied_coupon_code" : "",
    "discount_price" : "",
    "transaction_type" : "",
    "remaining_balance" : "",
    "grand_total" : ""

  }
]

在这里,只有前3个键有值。现在,如果我想给键添加一个值“COD” transaction_id 我如何实现它。。?

另外请注意,数组中的字典数并不总是2。它可以是任何数字。所以当我给键赋值“COD”时 事务处理id 无论字典的数量是多少,所有字典中的更改都应该更新。

到现在为止,我一直在尝试这样的东西。。

dictionary["transaction_id"] = "CASH"
arrayOfDictionary.append(dictionary)

但这又增加了一本字典,其值为 事务处理id 作为“现金”,总共提供2本词典,而不是2本。

2 回复 | 直到 8 年前

Yannick 8 年前

您可以迭代数组并更改 transaction_id 对于每个dict。

arrayOfDictionary.indices.forEach({ arrayOfDictionary[$0]["transaction_id"] = "COD" })

如果您想进行多个更新,只需在 forEach 环它将分别更改或添加值。

arrayOfDictionary.indices.forEach({
    arrayOfDictionary[$0]["transaction_id"] = "COD"
    arrayOfDictionary[$0]["anotherKey"] = "anotherValue"
})

{ } 到方括号 [ ]

var arrayOfDictionary = [
    [
        "sellingPrice" : "499",
        "id" : "5",
        "quantity" : "-2",
        "transaction_id" : "",
        "shipping_charges" : "",
        "payment_method" : "",
        "taxes" : "",
        "applied_coupon_code" : "",
        "discount_price" : "",
        "transaction_type" : "",
        "remaining_balance" : "",
        "grand_total" : ""
    ],
    [
        "sellingPrice" : "500",
        "id" : "8",
        "quantity" : "79",
        "transaction_id" : "",
        "shipping_charges" : "",
        "payment_method" : "",
        "taxes" : "",
        "applied_coupon_code" : "",
        "discount_price" : "",
        "transaction_type" : "",
        "remaining_balance" : "",
        "grand_total" : ""

    ]
]

Ahmad F 8 年前

为了简化答案,我假设字典中只有一个键。

你可以通过映射您当前的阵列,如下所示:

var myArray = [["transaction_id": ""], ["transaction_id": ""]]

myArray = myArray.map { (dict: [String: String]) -> [String: String] in
    var copyDict = dict
    copyDict["transaction_id"] = "COD"

    return copyDict
}

print(myArray)
// [["transaction_id": "COD"], ["transaction_id": "COD"]]