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如何删除“从字符串中引用”?[复制]

string ruby

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krunal shah · 技术社区 · 16 年前

ruby code for modifying outer quotes on strings?

这是我的绳子:

msgid """We couldn't set up that account, sorry.  Please try again, or contact an ""admin (link is above)."

我想删除所有的双引号,除了第一个和最后一个。

4 回复 | 直到 9 年前

1

Michael Kohl 16 年前

这是假设您的字符串始终是上面显示的“msgid…”格式,并且您的输入输出是“msgid”text here“':

>> str.gsub(/(msgid )"{1,}(.*) "{1,}(.*)"/, '\1"\2 \3"')
=> "msgid "We couldn't set up that account, sorry.  Please try again or contact an admin (link is above).""
>> puts str.gsub(/(msgid )"{1,}(.*) "{1,}(.*)"/, '\1"\2 \3"')
msgid "We couldn't set up that account, sorry.  Please try again or contact an admin (link is above)."

2

1

Tony Eichelberger 16 年前

这里有一个选项,只要你知道你总是希望在开头和结尾都有报价。

假设x拿着你想要操纵的刺。

x = '"' + x.gsub('"', '') + '"'

3

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the Tin Man 16 年前

msg = %q{msgid """We couldn't set up that account, sorry.  Please try again, or contact an ""admin (link is above)."}
print 'msgid "' << msg.sub('msgid ', '').gsub('"', '') << '"'
# >> msgid "We couldn't set up that account, sorry.  Please try again, or contact an admin (link is above)."

如果“msgid”在每一行前面,则将其删除,通过剥离双引号来处理双引号,然后将“msgid”放回原处,并再次添加所需的前导和尾随双引号。

4

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DarthJDG chetan borse 15 年前

由于双引号的字符串分隔符,msgid实际上是3个字符串。所以你可以:

msgid = ""<<"We couldn't set up that account, sorry. Please try again, or contact an "<<"admin (link is above)."

x = %q{}
  msgid = """We couldn't set up that account, sorry. Please try again, or contact an ""admin (link is above)."
  x << msgid
  x.gsub!('"', '')
  msgid = ""
  msgid << x
# Check
  puts x