如何从字符串中提取格式化部分

“\{[^}]+\}”的一些变体会不会不起作用?通过查找匹配项和从头到尾的子串来运行它。

以下代码不同于其他答案,因为它使用非贪婪匹配(“*”?):

    private static void Main(string[] args) {
        const string input = "Warning: the error {0} has occurred. {1, 9} module has {2:0%} done.";
        const string pattern = "{.*?}"; // NOTE: "?" is required here (non-greedy matching).
        var formattingParts = Regex.Matches(input, pattern).Cast<Match>().Where(item => item.Success).Select(item => item.Groups[0].Value);
        foreach (var part in formattingParts) {
            Console.WriteLine(part);
        }
    }

new Regex(@"\{[0-9:,% .]+\}");

在Java中 Matcher 类接受正则表达式并将返回所有匹配的子字符串。

String str = "Warning: the error {0} has occurred. {1, 9} module has {2:0%} done.";

Matcher matcher = pattern.matcher( "{.*}");
while (matcher.find()){
    String matched = matcher.group()
    \\do whatever you want with matched
}