子项上的Graphql筛选器[重复]

我试图理解Graph QL,并提供了一个基本的示例。e、 g.如果我通过此查询,我将返回与id匹配的结果。

query {
  person(id:"4090D8F6-EFC4-42CD-B55C-E2203537380C")
  {
    firstname
    surname
  }
}

我的数据只是一组静态的测试数据,我现在要做的是返回所有名与我提供的匹配的用户。我很困惑我该如何写这篇文章,因为id空检查似乎阻止了我!?

我的PersonQuery如下所示:

public class PersonQuery : ObjectGraphType<Person>
{

    public PersonQuery(ShoppingData data)
    {
        Field<PersonType>(
            "person",
            description: "A Person",
            arguments: new QueryArguments(
                new QueryArgument<NonNullGraphType<IdGraphType>>
                {
                    Name = "id",
                    Description = "The id of the person"
                }),
            resolve: ctx =>
            {
                return data.GetById(ctx.GetArgument<Guid>("id"));
            });

    }
}

我该怎么做才能按名字返回一个人员列表,我不知道下面的查询是否有效,但我想知道如何与工作id示例一起执行此操作。

query {
  person
  {
    firstname: ("Andrew")
    surname
  }
}

答案更新-由DavidG提供

我按照前面提到的那样做了,所以我的PersonQuery现在看起来像这样

public class PersonQuery : ObjectGraphType<Person>
    {

        public PersonQuery(ShoppingData data)
        {
            Field<PersonType>(
                name: "person",
                description: "A Person",
                arguments: new QueryArguments(
                    new QueryArgument<IdGraphType>
                    {
                        Name = "id",
                        Description = "The id of the person"
                    }),
                resolve: ctx =>
                {
                     return data.GetById(ctx.GetArgument<Guid>("id"));
                });

            Field<ListGraphType<PersonType>>(
                name : "persons",
                description: "Persons",
                arguments: new QueryArguments(
                    new QueryArgument<StringGraphType>
                    {
                        Name = "firstname",
                        Description = "The firstname of the person"
                    },
                    new QueryArgument<StringGraphType>
                    {
                        Name = "surname",
                        Description = "The surname of the person"
                    }),
                resolve: ctx =>
                {
                    var firstName = ctx.GetArgument<String>("firstname");
                    var surname = ctx.GetArgument<String>("surname");
                    return data.Filter(firstName, surname);
                });

        }
    }

然后,我可以按如下方式运行graphql查询:

query {
  persons(firstname: "Andrew", surname: "P")
  {
    firstname
    surname
  }
}