要在没有任何额外依赖项的情况下执行此操作,可以使用
Process.Start
通过命令行模拟启动。以下是包装并提供此功能的类:
public class DockerStarter : IDisposable
{
private const string DOCKER_COMPOSE = @"c:\Program Files\Docker\Docker\resources\bin\docker-compose.exe";
public string ComposeFile { get; set; }
public string WorkingDir { get; set; }
public DockerStarter(string composeFile, string workingDir)
{
ComposeFile = composeFile;
WorkingDir = workingDir;
}
public void Start()
{
var startInfo = generateInfo("up");
_dockerProcess = Process.Start(startInfo);
// TODO: Find better way to wait for Docker containers to start
Thread.Sleep(1000);
}
private Process _dockerProcess;
public void Dispose()
{
_dockerProcess.Close();
var stopInfo = generateInfo("down");
var stop = Process.Start(stopInfo);
stop.WaitForExit();
}
private ProcessStartInfo generateInfo(string argument)
{
var procInfo = new ProcessStartInfo
{
FileName = DOCKER_COMPOSE,
Arguments = $"-f {ComposeFile} {argument}",
WorkingDirectory = WorkingDir
};
return procInfo;
}
}
显然,这种方法有缺点:
-
固定路径到
docker-compose
可执行文件
-
手动等待容器启动
我会看看是否有更好的方式直接与Docker守护进程交互,并在可能的情况下更新答案。