此代码段中是否有无法访问的代码?我不这么认为,但雷斯哈珀不是这样告诉我的

变量 narrativefound 当控件到达该语句时永远不会为真:

narrativefound = true;
// ...
break;  // This causes control to break out of the loop.

我想Resharper是想告诉你 narrativefound == false 永远都是真的。

你不需要 narrativeFound 变量。在你设定它为真的范围内,你打破了 foreach 循环。如果你不把它设为真,你就不会打破,然后你加上 newNarrative 到 newNarrativeList .

所以,这个可以重写为

foreach (Narrative newNarrative in newChassis.Narratives)
{
     foreach (Narrative orig in asMaintained.Narratives)
     {
            if (string.Compare(orig.PCode, newNarrative.PCode) == 0)
            {
                      if (newNarrative.NarrativeValue.Trim().Length != 0)
                      {
                         orig.NarrativeValue = newNarrative.NarrativeValue;
                         newNarrativeList.Add(orig);                            
                      }
                      break;
            }

            newNarrativeList.Add(newNarrative);                 
     }
}

这是你代码中的一个错误。

foreach (Narrative newNarrative in newChassis.Narratives) 
{ 
     bool narrativefound = false;  

     foreach (Narrative orig in asMaintained.Narratives) 
     { 
            if (string.Compare(orig.PCode, newNarrative.PCode) ==0 ) 
            { 
                      narrativefound = true; 
                      if (newNarrative.NarrativeValue.Trim().Length != 0) 
                      { 
                         orig.NarrativeValue = newNarrative.NarrativeValue; 
                         newNarrativeList.Add(orig);                             
                      } 
// narrativeFound == true, but now we exit the for loop
                      break; 
            } 
// narrativeFound is always false here.  The test is redundant
            if (narrativefound == false) 
            { 
                 newNarrativeList.Add(newNarrative);  
            } 
     } 
} 

R是正确的,因为如果你把叙述变为真实,你就在你设定好它之后,从前臂中挣脱出来。

我相信它告诉你,因为如果narrativefound设置为true,那么for循环将退出(break;)。因此,如果对if(narrativeFound==false)进行评估,则其值始终为false。