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通过h3含量nokogiri之间的<p>提取

nokogiri ruby

0

Fabián · 技术社区 · 9 年前

我只想提取 <p>

require 'nokogiri'
require 'open-uri'
require 'time'

@url = "http://www.caru.org.uy/web/servicios/llamados-a-concurso-publico-para-contratar-personal/"

page = Nokogiri::HTML(open(@url))
div_content = page.css('.contenido')

div_content.each do |item|

   puts item.text

   break if  item.css('h3').text == "Finalizados"

end

1 回复 | 直到 9 年前

1

0

pguardiario 9 年前

你应该能够做到:

css = 'h3:contains(Vigentes) ~ p:has(~ h3:contains(Finalizados))'

xpath = "//h3[contains(text(), 'Vigentes')]/following-sibling::p[./following-sibling::h3[contains(text(), 'Finalizados')]]"
page.search(xpath).each do |p|
  # do something
end